Bi B2 A 1 3 4 3 2 6 B 5 1 8 B3 1 (10.84 KiB) Viewed 60 times
Show that the equation
Ax = b does not have a solution for all possible b, and
describe the set of all b for which Ax = b does have a
solution.
bi b2 : A= 1 -3 -4 -3 2 6 , b = 5 -1 -8 = b3
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