What percentage of the population live in their state of birth? According to the U.S. Census Bureau's 2014 American Comm

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What percentage of the population live in their state of birth? According to the U.S. Census Bureau's 2014 American Comm

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What percentage of the population live in their state of birth? According to the U.S. Census Bureau's 2014 American Community Survey, the figure ranges from 25% in Nevada to 78.7% in Louisiana. The average percentage across all states and the District of Columbia is 57.7%. The data in the file HomeState are consistent with the findings in this American Community Survey. The data are for a random sample of 120 Arkansas residents and for a random sample of 180 Virginia residents (a) Formulate hypotheses that can be used to determine whether the percentage of stay-at-home residents in the two states differs from the overall average of 57,7% H₂20.577 H, P<0.577 H₂ P<0.577 H₂020.577 M₂P0577 H, p≤0.577 H₂p=0577 H. 0577 H50577 H₂P0577 (D) Estimate the proportion of stay-at-home residents in Arkansas. (Round your answer to four decimal places) Does this proportion after significantly from the mean proportion for at states? Use 0.05. Find the value of the test statistic. (Round your answer to two decimal places) Find the value (Round your answer to four decal places) What is your condusion? Do not reject There is sufficient evidence to conclude that the protion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Do not reject H, There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Reject There is insufficent evidence to conclude that the proportion of stay-at-home residents in Arkansas effers from the overall proportion of 0.577 Reject H. There is sufficient evidence to conclude that the proportion of stay at-home residents in Arkansas offers from the overall proportion of 0.577

(c) Estimate the proportion of stay-at-home residents in Virginia. (Round your answer to four decimal places) Does this proportion offer significantly from the mean proportion for at states? Use -0.05. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) D-value- What is your conclusion? Reject M. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject H. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject H. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Reject H. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577 (d) Would you expect the proportion of stay-at-home residents to be higher in Virginia than in Arkansas? Support your conclusion with the results obtained in parts (b) and (c) from the results obtained in parts (b) and (c), we would expect the number of stay-at-home residents to be in Arkansas than Virginia The sample results show that, rounded to two decimal places, the estimated percentage of Arkansas residents who were born there is percentage of Virginia residents who were born there is %. The sample results also show that, rounded to two decimal places, the estimated

You may need to use the appropriate appendix table or technology to answer this question. What percentage of the population live in their state of birth? According to the U.S. Census Bureau's 2014 American Community Survey, the figure ranges from 25% in Nevada to 78.7% in Louisiana. Th average percentage across all states and the District of Columbia is 57.7%. The data in the file HomeState are consistent with the findings in this American Community Survey. The data are for a randor sample of 120 Arkansas residents and for a random sample of 180 Virginia residents. (a) Formulate hypotheses that can be used to determine whether the percentage of stay-at-home residents in the two states differs from the overall average of 57.7% Hop20.577 HP <0.577 Ho: <0.577 Hp0.577 HP>0.577 HP≤0.577 p=0.577 HD*0.577 HP ≤0.577 HP>0.577 (b) Estimate the proportion of stay-at-home residents in Arkansas. (Round your answer to four decimal places.) Does this proportion differ significantly from the mean proportion for all states? Use a 0.05. Find the value of the test statistic (Round your answer to two decimal places) Find the p-value. (Round your answer to four decimal places) pivalue= What is your conclusion? Do not reject H There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas offers from the overall proportion of 0.577 Do not reject He There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas offers from the overall proportion of 0.577 Reject H There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas offers from the overal proportion of 0.577. Reject H There is sufficient evidence to conclude that the eroportion of stay-at-home residents in Arkansas differs from the overal proportion of 0.577

(c) Estimate the proportion of stay-at-home residents in Virginia. (Round your answer to four decimal places.) Does this proportion differ significantly from the mean proportion for all states? Use a 0.05. Find the value of the test statistic (Round your answer to two decimal places) Find the p-value. (Round your answer to four decimal places.) p-value= What is your conclusion? Reject H. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject H There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577 Do not reject H There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577 Reject H. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. (d) Would you expect the proportion of stay-at-home residents to be higher in Virginia than in Arkansas? Support your conclusion with the results obtained in parts (b) and (c) in Arkanses than Virginia. The sample results show that, rounded to two from the results obtained in parts (b) and (c), we would expect the number of stay-at-home residents to be decimal places, the estimated percentage of Arkansas residents who were bom there is percentage of Virginia residents who were born there is %. The sample results also show that, rounded to two decimal places, the estimated
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