The 300-kg concrete block is elevated by the hoisting mechanism shown below where the cables are securely wrapped around
Posted: Tue Jul 12, 2022 8:40 am
The 300-kg concrete block is elevated by the hoisting mechanismshown below where the cables are securely wrapped around therespective drum. The drum, which are fastened together and turn asa single unit about their mass center at O, have acombined mass of 150 kg and a radius of gyration about Oof 450 mm. If a constant tension P of 1.80 kN ismaintained by the power unit at A,
m = 150 kg ko = 450 mm 600 mm 300 kg 300 mm P = 1.80 kN 45° ㅗ of ZARAMAYA M
1 a) SKETCH FREE BODY DIAGRAM b) [I = k²m] I= ? [ΣΜ = 1a] [ΣΕ, = may] a=? T=? Ī = 10 = (0.450)² 150 lo 1.80(10³) (0.600) T OT = √√0(x)² + (0(y)² От OT = x T(0.300) = 30.4a 300(9.81)= 300a c) [ΣΕ = 0] O 1.80(10³) cos 45º = 0 0x =? [ZF, = 0] 0,- 150(9.81) — 3252 - 1.80(10³) sin 45° = 0, 0, = 5996 N - O(y)=?
- The 300 Kg Concrete Block Is Elevated By The Hoisting Mechanism Shown Below Where The Cables Are Securely Wrapped Around 1 (93.4 KiB) Viewed 40 times
1 a) SKETCH FREE BODY DIAGRAM b) [I = k²m] I= ? [ΣΜ = 1a] [ΣΕ, = may] a=? T=? Ī = 10 = (0.450)² 150 lo 1.80(10³) (0.600) T OT = √√0(x)² + (0(y)² От OT = x T(0.300) = 30.4a 300(9.81)= 300a c) [ΣΕ = 0] O 1.80(10³) cos 45º = 0 0x =? [ZF, = 0] 0,- 150(9.81) — 3252 - 1.80(10³) sin 45° = 0, 0, = 5996 N - O(y)=?