Answer Happy

@ RL B/S (m) I/S (m) F/S (m) HI (m) (MAMSL) 0.666 124.122 123.456 0.570 123.552 0.634 123.488 Remarks BM SIOS 0-000 0-025 0-050 0-075 0.681 123.44-1 0.710 123.412 0.690 123.432 0+100 0.033 1.705 122.45 122.417 2.891 119.599 4.596 TP 2 BM S102 M W 0.699 6 checks EBS- EFS = Last RL- First RL -> 0-699-4.596 = 119.539 - 123.456 - 3.897 - 3.897 Slope = RL₂5-RL, 75-25 xlow XIR 123.438-123.412 50 = 0.152 % Ane
Question 2 On a graph paper OR drafting software (for example AutoCAD) use appropriate horizontal and vertical scales to produce a longitudinal section of the centre line of the existing road from chainage 0+000 to chainage 0+100 in question 1 above. Plan should have appropriate map components (horizontal and vertical scales, orientation, title) [10 marks Question 3 Using the plan prepared in question 2, design a new road with a horizontal formation level from 0+000 to 0+100 that is 124.000mAMSL. For each cross-section the existing ground slopes upward from left to right, at a gradient of 1:8, the formation-width being 20m and the side slopes 1:1.5. 1) Show on the plan (in red ink) the formation level of the road. [2 marks] ii) Using the plan determine the depth of cut or fill at each chainage in ground units 15 marks iii) Calculate the area for each section. [15 marks iv) Calculate the volume of excavation from 0+000 to 0+100. [3 marks]