- V1 Vcc Q3 R 5 71k Vcc Rc1 2k Q1 Vee Q4 Vcc Q2 Rc2 2k Vcc 12v Vee 12v C1 V2 Vout Fig 2 32 2 32 1 All The Transistor 1 (41.64 KiB) Viewed 26 times
v1 Vcc Q3 R 5.71k Vcc Rc1 2k Q1 Vee Q4 Vcc Q2 Rc2 2k Vcc = 12V Vee = -12V C1 v2 vout Fig 2.32 2.32 1. All the transistor
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v1 Vcc Q3 R 5.71k Vcc Rc1 2k Q1 Vee Q4 Vcc Q2 Rc2 2k Vcc = 12V Vee = -12V C1 v2 vout Fig 2.32 2.32 1. All the transistor
v1 Vcc Q3 R 5.71k Vcc Rc1 2k Q1 Vee Q4 Vcc Q2 Rc2 2k Vcc = 12V Vee = -12V C1 v2 vout Fig 2.32 2.32 1. All the transistors in the circuit shown have ß = 100. But note the different Early Voltages! Q1 and Q2 have VA = 00, while Q3 and Q4 have VA = 88.7V. Consider Vid=v1 - v2 and Vic is (v1 + v2)/2. Find (a) the differential mode gain, (b) find the common mode gain, (c) the CMRR(dB).