Answer Happy

For the following Ips, write the network name, give 2 Ips in the same network, find the number of the possible Ips 11.45.3.5 → 180.90.27.89→ 190.35.177.98 → 192.76.19.1→ • 200.30.50.90 ➜ Net name 100.100.100.100 ➜ • 107.39.50.20 ➜ 1st ip 2nd IP no. of valid IPs
For the following Ips, write the network name, BC address, Prefix length, and the default mask 11.45.3.5 → Net name 180.90.27.89→ . 190.35.177.98 → 192.76.19.1→ • 200.30.50.90 ➜ • 100.100.100.100 ➜ • 107.39.50.20 ➜ 192.3.5.6 → BC Prefix length default mask