The Figure Below Represents An Intersection Of Two Streets Sensors Have Been Placed In The Proximity Of The Intersectio 1 (70.89 KiB) Viewed 75 times
The Figure Below Represents An Intersection Of Two Streets Sensors Have Been Placed In The Proximity Of The Intersectio 2 (29.12 KiB) Viewed 75 times
The figure below represents an intersection of two streets. Sensors have been placed in the proximity of the intersection, along A, B, C and D lanes to detect vehicles' presence. A sensor's output is 1 when there is no vehicle on its monitored lane (indicated as free in the following) and O when a vehicle is present (busy lane). The two sets of intersection lights (East-West or EW, and North-South or NS) observe the following logic: 1) The EW lights will turn green when vehicles will be simultaneously detected on both C and D lanes. 2) The EW lights will also be green when either C is busy or D is busy, and, if A and B are not both busy at the same time. 3) The NS lights will be green when vehicles will be sensed on both A and B lanes, and, if C and D are not simultaneously busy. 4) The NS lights will also turn green when either A is busy or B is busy, but C and D are both free. 5) The EW lights will also be green when no vehicle is present in the intersection. N *_ A CE NS B D
a) Using sensors A, B, C, D as input variables, implement a logical combinational circuit that controls the lights. There will be 2 output functions NS(A,B,C,D) and EW(A,B,C,D) whose values will be 1 when the light is green (and 0 for the red!). Simplify the 2 functions and derive their Sum-of-Products minimal form (no logic diagram asked). b) Realize NS(A,B,C,D) and EW(A,B,C,D) using a 4-to-16 decoder and 2 OR gates; draw the circuit diagram.
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