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A glass sheet 1.20 µm thick is suspended in air. In reflected light, there are gaps in the visible spectrum at 573 nm and 645.00 nm. Calculate the minimum value of the index of refraction n of the glass sheet that produces this effect. n =
For the optical fiber shown in the figure, find the minimum angle of incidence (0;) that will result in total internal reflection if the refractive index for the cladding (n₂) is 1.44 and the refractive index of the core is (A.) n₁ = 1.52 and (B.) n₁ = 1.80. Cone of acceptance A. 0; Σ 0. I n₁ Cladding (n₂) o Core 。 Β. 0; >