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The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 85.0 nC . The plates
Posted: Mon Jul 11, 2022 2:34 pm
by answerhappygod
- The Plates Of A Parallel Plate Capacitor Are 2 50 Mm Apart And Each Carries A Charge Of Magnitude 85 0 Nc The Plates 1 (58.48 KiB) Viewed 42 times
- The Plates Of A Parallel Plate Capacitor Are 2 50 Mm Apart And Each Carries A Charge Of Magnitude 85 0 Nc The Plates 2 (50.82 KiB) Viewed 42 times
The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 85.0 nC . The plates are in vacuum. The electric field between the plates has a magnitude of 5.00×106 V/m. You may want to review (Pages 786 - 790). For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. ▼ Part A What is the potential difference between the plates? V = 1.25x104 V Submit Previous Answers Correct IDENTIFY: The capacitance depends on the geometry (area and plate separation) of the plates. SET UP: For a parallel-plate capacitor, Vab = Ed. EXECUTE: Vab = Ed = (5.00 x 106 V/m) (2.50 x 10-³ m) = 1.25 × 10¹ V.
▼ ▼ Part B What is the area of each plate? S= Submit Part C -ΨΕΙ ΑΣΦ C= What is the capacitance? Submit Request Answer VE ΑΣΦ → PASSE ? SEAD Previous Answers Request Answer ? m² F