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In a human population of 10,000, the frequency of individuals that have cystic fibrosis is 1 in 2500. Cystic fibrosis is an autosomal recessive trait. This population is in HW equilibrium. Calculate the genotype frequency and number of heterozygous individuals in this population. Genotype frequency = 0.039 Total heterozygotes in population = 392 Genotype frequency = 0.961 Total heterozygotes in population - 9608 Genotype frequency = 0.02 Total heterozygotes in population - 392 =
Genotype frequency = 0.98 Total heterozygotes in population = 392 Genotype frequency = 0.961 Total heterozygotes in population = 392 Genotype frequency = 0.039 Total heterozygotes in population = 9608 O Genotype frequency = 0.02 Total heterozygotes in population = 9608 Genotype frequency = 0.98 Total heterozygotes in population = 9608 Hide hint for Question 12 Individuals that are homozygous recessive for cystic fibrosis would be... CF/CF, CF/cf or cf/cf??? 1= √√√₁²