Answer Happy

Posted: **Mon Jul 11, 2022 2:04 pm**

: Before Mix Celcius Hci And After Mix Celcius 2 00m Hci 2 02m Naoh 40 0 30 0 20 0 10 0 0 0 0 00 Before Mix Celcius 1 (27.71 KiB) Viewed 47 times

: Before Mix Celcius Hci And After Mix Celcius 2 00m Hci 2 02m Naoh 40 0 30 0 20 0 10 0 0 0 0 00 Before Mix Celcius 2 (38.25 KiB) Viewed 47 times

Before mix (celcius) HCI and After mix (celcius) 2.00M HCI+2.02M NaOH 40.0 30.0 20.0 10.0 0.0 0.00 Before mix (celcius) HCI After mix (celcius) 2.00M HCI+2.02M NaOH 2.00 -0.0457*x + 20 R² = 0.686 4.00 Time -0.353*x + 34.3 R² = 0.983 6.00 8.00
mass of empty cup = 1.91579. mass of cup + mix= 113.64999 เรา mass of mixture = 111.73429 initial temp & = Final temp = Need 437.6°C 97.7°C A. temp change (At) B. total heat evolved in reaction (Altn) C. # of moles of H₂O formed D. Molar heat of neutralization (Alt n) E. Molar heat of neutralization calculated from Hess's law F.% difference between experimental & calculated valves.