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Question 1 A galvanic cell is made with a metal "X" electrode placed in a 1.0 M solution of metal "X" sulfate, XSO, making up one half-cell and metal "Y" electrode placed in a 1.0 M solution of metal "Y" sulfate, YSO, making up the other half-cell. The resulting galavanic cell is pictured below. Fill in the following statements as related to the galvanic cell pictured below. XSO (aq) Salt Bridge YSO4(aq) Part 1: 0 out of 3 Part 2: 0 out of 3 Part 3: 0 out of 3 Part 4: 0 out of 3 * Points:0 out of 12 Reduction occurs in the half-cell with the "X" electrode. The X electrode will increase in mass. The cations in the salt bridge will flow toward the half cell with the X electrode. The reaction occurring with the lower reduction potential is in the half-cell with the Yelectrode.
Question 2 Given the following cell notation for a galvanic cell, calculate the cell potential. E = 2.4 cell Question 3 B.O V Which of the following reactions is NOT spontaneous as written? A. D. O Mg(s) | Mg²+ (aq) || Ni²+ (aq) | Ni(s) Ag+ (aq) + Fe²+ (aq) → Fe³+ (aq) + Ag(s) 2 Al(s) + 3 12 (s) → 2 A1¹¹ (aq) + 61¯ (aq) 2 H+ (aq) + Zn(8) → Zn²+ (aq) + H₂(g) Ni²+ (aq) + 2 Cl(aq) → Ni(s) + Cl₂(g) Use the following description of a galvanic cell to answer questions 4-7. x Points:0 out of 10 * Points:0 out of 10