PLEASE ANSWER ALL PART OF THE QUESTION, ATTACH PICTURES ARE OF LAB LECTURE AND RESULTS PLEASE, GET ALL CALCULATIONS SHOW
Posted: Mon Jul 11, 2022 2:02 pm
PLEASE ANSWER ALL PART OF THE QUESTION, ATTACH PICTURES ARE OF LAB LECTURE AND RESULTS PLEASE, GET ALL CALCULATIONS SHOWN IN THE PICTURE ATTACHED.
Third column for your unknown salt. The Mean enthalpy at the bottom only applies to trials 1 and 2 with NaNO3, do not average the third trial (unknown). For the unknown calculate only the heat (q), not the enthalpy.
QUESTION1)
A)The calorimeter used in the experiment is supposed to isolate the system and avoid any scape of heat. Do you think this is true for our experimental setup? Indicate the errors and ways how the heat could have scaped.
B) Hot and cold packs are common items in sports. Research on the chemicals that are inside hot and cold packs. Mention at least 2 for each.
C) Assuming the minimum requirements for spontainety, determine the entropy change in J/(mol.K). Consider a temperature of 300K for your calculations.
Exp 18. SPONTANEITY Goal: Determine the thermodynamic parameters (AH, AS, AG) for the dissolution of NaNO3 in water and an unknown. NaNO3 (5) Na (ag) + NO3(aq) = AG=AH-TAS + Spontaneous is the requirement 0=AH-TAS AH = TAS AS = A#
Procedure 0.85 0.85 with Nancy X2 with unknown xl 100ml ti dk₂0 add N₂ ND3 stir SE one each student Swirl stir, take temp every 3088) max or min temp = tf Calculations Na Mz Na + NU3 SH 9rxn = q sol + q cal quxn = ATC m + Cal AT Gran = (Tt-Ti) (41843_) (mass) + 10_5 (T+7 °C 91x0 = 1 днухи = Якха Инапоз in kJ/mul
100mL of 0.1M NaNOS M = M x V x MM = 0.1 × 0.1 × 85 m = 0,85 g NaNO₂ use same mass for unknown
Spontaneity Results Trial Mass of NaNO, and paper (g) Mass of paper (g) Mass of NaNO) (g) 4(°C) Temperature (°C) after M°C 30 s 60 s 90 s 120 s 150 s 180 s 210 s 240 s g(system) (J) AH (kJ/mol) 0.07009 0-9925 -0.85g 22.7°C 23.0c 21.6 22-2 21-6 22-1 22-1 22-2 22-1 22.2 22.1 Unknown Trial #13 2 2.715 2.8631 20125 1.8540 0.85g 0.85g 25-2 22.7 24.4 22.177 24.7 22-7 24-8 22.7 24.8 22.8 24.8 22-8 248 22.9 24.9 22.9 24.9 22.9 24.9 Mean AH (kJ/mol) 315 37 C Learning. All Rights Reserved. May not be scanned copied or duplicated, or posted to a publicly accessible website, in whole or in part
Third column for your unknown salt. The Mean enthalpy at the bottom only applies to trials 1 and 2 with NaNO3, do not average the third trial (unknown). For the unknown calculate only the heat (q), not the enthalpy.
QUESTION1)
A)The calorimeter used in the experiment is supposed to isolate the system and avoid any scape of heat. Do you think this is true for our experimental setup? Indicate the errors and ways how the heat could have scaped.
B) Hot and cold packs are common items in sports. Research on the chemicals that are inside hot and cold packs. Mention at least 2 for each.
C) Assuming the minimum requirements for spontainety, determine the entropy change in J/(mol.K). Consider a temperature of 300K for your calculations.
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Procedure 0.85 0.85 with Nancy X2 with unknown xl 100ml ti dk₂0 add N₂ ND3 stir SE one each student Swirl stir, take temp every 3088) max or min temp = tf Calculations Na Mz Na + NU3 SH 9rxn = q sol + q cal quxn = ATC m + Cal AT Gran = (Tt-Ti) (41843_) (mass) + 10_5 (T+7 °C 91x0 = 1 днухи = Якха Инапоз in kJ/mul
100mL of 0.1M NaNOS M = M x V x MM = 0.1 × 0.1 × 85 m = 0,85 g NaNO₂ use same mass for unknown
Spontaneity Results Trial Mass of NaNO, and paper (g) Mass of paper (g) Mass of NaNO) (g) 4(°C) Temperature (°C) after M°C 30 s 60 s 90 s 120 s 150 s 180 s 210 s 240 s g(system) (J) AH (kJ/mol) 0.07009 0-9925 -0.85g 22.7°C 23.0c 21.6 22-2 21-6 22-1 22-1 22-2 22-1 22.2 22.1 Unknown Trial #13 2 2.715 2.8631 20125 1.8540 0.85g 0.85g 25-2 22.7 24.4 22.177 24.7 22-7 24-8 22.7 24.8 22.8 24.8 22-8 248 22.9 24.9 22.9 24.9 22.9 24.9 Mean AH (kJ/mol) 315 37 C Learning. All Rights Reserved. May not be scanned copied or duplicated, or posted to a publicly accessible website, in whole or in part