Page 1 of 1

4.2.8 The infiltration into a Yolo light clay as a function of time for a steady rainfall tate of 0.5 cm/h is as follows

Posted: Mon Apr 25, 2022 9:00 am
by answerhappygod
4 2 8 The Infiltration Into A Yolo Light Clay As A Function Of Time For A Steady Rainfall Tate Of 0 5 Cm H Is As Follows 1
4 2 8 The Infiltration Into A Yolo Light Clay As A Function Of Time For A Steady Rainfall Tate Of 0 5 Cm H Is As Follows 1 (14.21 KiB) Viewed 50 times
4 2 8 The Infiltration Into A Yolo Light Clay As A Function Of Time For A Steady Rainfall Tate Of 0 5 Cm H Is As Follows 2
4 2 8 The Infiltration Into A Yolo Light Clay As A Function Of Time For A Steady Rainfall Tate Of 0 5 Cm H Is As Follows 2 (14.21 KiB) Viewed 50 times
4 2 8 The Infiltration Into A Yolo Light Clay As A Function Of Time For A Steady Rainfall Tate Of 0 5 Cm H Is As Follows 3
4 2 8 The Infiltration Into A Yolo Light Clay As A Function Of Time For A Steady Rainfall Tate Of 0 5 Cm H Is As Follows 3 (19.67 KiB) Viewed 50 times
4.2.8 The infiltration into a Yolo light clay as a function of time for a steady rainfall tate of 0.5 cm/h is as follows (Skaggs, 1982): Time (h) Cumulative infiltration (cm) Infiltration rate (em/h) 0 1.07 1.53 2.30 3.04 3.89 4.85 7.06 0 0.54 0.75 1.0 1.2 1.4 1.6 2.0 0.5 0.5 0.37 0.29 0.25 0.22 0.20 0.17

parameters fo. fe, and-k for Horton's equation. Assume that ponding occurs at t = 1.07 h. 4.2.9 Determine the parameters for Philip's equation for the infiltration data given in Prob. 4.2.8. 4.2.10 Parameters in Philip's equation for a clay soil are $ - 45 cm.h -1/2 and K = 10 cm/h. Determine the cumulative infiltration and the infiltration rate at 0.5-hour increments for a 3-hour period. Plot both as functions of time