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For the following reaction, 29.5 grams of sulfur dioxide are allowed to react with 6.13 grams of oxygen gas. sulfur diox

Posted: Mon Jul 11, 2022 1:55 pm
by answerhappygod
For The Following Reaction 29 5 Grams Of Sulfur Dioxide Are Allowed To React With 6 13 Grams Of Oxygen Gas Sulfur Diox 1
For The Following Reaction 29 5 Grams Of Sulfur Dioxide Are Allowed To React With 6 13 Grams Of Oxygen Gas Sulfur Diox 1 (9.68 KiB) Viewed 38 times
For the following reaction, 29.5 grams of sulfur dioxide are allowed to react with 6.13 grams of oxygen gas. sulfur dioxide ( g ) + oxygen ( g ) →→→ sulfur trioxide (g) What is the maximum amount of sulfur trioxide that can be formed? What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams grams