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For the reaction below, the equilibrium constant is Kc= 3.2×10-10 at 25 °C. Pb(s) + 2 Cr³+ (aq) = Pb²+ (aq) + 2 Cr²+ (aq
Posted: Mon Jul 11, 2022 1:54 pm
by answerhappygod
- For The Reaction Below The Equilibrium Constant Is Kc 3 2 10 10 At 25 C Pb S 2 Cr Aq Pb Aq 2 Cr Aq 1 (35.66 KiB) Viewed 34 times
For the reaction below, the equilibrium constant is Kc= 3.2×10-10 at 25 °C. Pb(s) + 2 Cr³+ (aq) = Pb²+ (aq) + 2 Cr²+ (aq) 2+, 3+ Excess Pb(s) is added to a solution for which the initial concentration of Cr³+ (aq) is 1.2 mol L-1. What are the equilibrium concentrations of Pb2+ and Cr²? Enter values accurate to 2 significant figures. Do not include units. [Pb²+]eq = Number [Cr2+ Jea = Number mol L mol L-1