Each step in the following process has a yield of 80.0%. CH+4CLCCI, + 4 HCI CCI +2HF- . CCI₂F₂ + 2HCI The CCI, formed in
Posted: Mon Jul 11, 2022 1:37 pm
Each step in the following process has a yield of 80.0%. CH+4CLCCI, + 4 HCI CCI +2HF- . CCI₂F₂ + 2HCI The CCI, formed in the first step is used as a reactant in the second step. If 7.50 mol CH₂ reacts, what is the total amount of HCI produced? Assume that Cl, and HF are present in excess. moles HCI: mol