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The formation constant* of [M(CN)412 is 7.70 x 10¹6, where M is a generic metal. A 0.140 mole quantity of M(NO3)2 is add

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The formation constant* of [M(CN)412 is 7.70 x 10¹6, where M is a generic metal. A 0.140 mole quantity of M(NO3)2 is add

Posted: Mon Jul 11, 2022 1:25 pm
by answerhappygod
The Formation Constant Of M Cn 412 Is 7 70 X 10 6 Where M Is A Generic Metal A 0 140 Mole Quantity Of M No3 2 Is Add 1
The Formation Constant Of M Cn 412 Is 7 70 X 10 6 Where M Is A Generic Metal A 0 140 Mole Quantity Of M No3 2 Is Add 1 (64.19 KiB) Viewed 19 times
The formation constant* of [M(CN)412 is 7.70 x 10¹6, where M is a generic metal. A 0.140 mole quantity of M(NO3)2 is added to a liter of 0.940 M NaCN solution. What is the concentration of M2+ ions at equilibrium? [M²+] =
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