Can someone explain to me how he got 3.9 as well as the general formula and the numbers he substituted for this problem.
Posted: Mon Jul 11, 2022 1:16 pm
Can someone explain to me how he got 3.9 as well as the generalformula and the numbers he substituted for this problem.Thanks.
Which of the ff. obtained by free radical A 38.8% B 15.3% C. 30.6% D. 45.9% please help. Show how to compute and explain. Thanks. Show transcribed data Expert Answer Anonymous answered this 1,403 answers Answer: The correct answer is D. 45.9% ✰ answers.com 1° vs 2° Product ratio = 1 : 3.9 Explanation: The relative yields of the 3 possible chlorination products of 2,2-dimethylbutane are as follows: wrresponds to the % yield of 1- chloro-2, 2-dimethy) but ane 2,2-dimethyl but are chlorination with Thanks! % 1-chloro-2,2-dimethylbutane = [100 x (9 x 1)]/[(12 x 1 + 2 x 3.9)] = 100 x 9/19.8 = 45.5% % 3-chloro-2,2-dimethylbutane = [100 x (2 x 3.9)]/[(12 x 1 + 2 x 3.9)] = 100 x 7.8/19.8 = 39.4% % 1-chloro-3,3-dimethylbutane = [100 x (3 x 1)]/[(12 x 1 + 2 x 3.9)] = 100 x 3/19.8 = 15.1%
Which of the ff. obtained by free radical A 38.8% B 15.3% C. 30.6% D. 45.9% please help. Show how to compute and explain. Thanks. Show transcribed data Expert Answer Anonymous answered this 1,403 answers Answer: The correct answer is D. 45.9% ✰ answers.com 1° vs 2° Product ratio = 1 : 3.9 Explanation: The relative yields of the 3 possible chlorination products of 2,2-dimethylbutane are as follows: wrresponds to the % yield of 1- chloro-2, 2-dimethy) but ane 2,2-dimethyl but are chlorination with Thanks! % 1-chloro-2,2-dimethylbutane = [100 x (9 x 1)]/[(12 x 1 + 2 x 3.9)] = 100 x 9/19.8 = 45.5% % 3-chloro-2,2-dimethylbutane = [100 x (2 x 3.9)]/[(12 x 1 + 2 x 3.9)] = 100 x 7.8/19.8 = 39.4% % 1-chloro-3,3-dimethylbutane = [100 x (3 x 1)]/[(12 x 1 + 2 x 3.9)] = 100 x 3/19.8 = 15.1%