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ed ed PM (14%) Problem 4: A wire, bent into a rectangle with sides a 0.075 m and b=0.015 m, is in a magnetic field B directed perpendicularly to the face of the wire, as shown. The perpendicular component is a function of time as B(t)=Asin(ost), where 4-0.25 T, 6-4 rad/s. In this problem. take the normal vector to the surface of the loop to be parallel to the magnetic field. eted indexpertia.comtcking it 7M79-75-94-44/100-32171 bn duce with Expen TA'S Test Servi copying this information to my soos sharing website is strictly forbidden Doing sàn thay sealt in termination of 25% Part (a) Express the magnetic flux going through the wire, d, in terms of a, b, d, e, and f cos(a) cos(p) costot) cos(8) sin(a) sin(0) sincot) sin(0) b a do sin(9) A L Subout Hest C N 78 456 123 29 + . 0 NO OLX C I give up! dabartinn noe fonthuck B TH Otheespertta.com Grade Summary Deductions Potential Tit 100% Attempts rentaining: 5 (per attemp detailed in
eted leted (14%) Problem 4: A wire, bent into a rectangle with sides a 0.075 m and b=0.015 m, is in a magnetic field B directed perpendicularly to the face of the wire, as shown. The perpendicular component is a function of time as B(t)=Asin(et), where A-0.25 T, co-4 radis. In this problem, take the normal vector to the surface of the loop to be parallel to the magnetic field. Wat [email protected] mpleted @hexperta.com-tricking id 7M79-13-94-44-900A-32171 ts accondance with Expert TA's Terms of Service copying this formations sey solutions sharing white is strictly biddo Ding may ret i sation of 25% Part (a) Express the magnetic flux going through the wire, , in terms of a, b, d, e, and f 25% Part (b) Express the the emf, e, induced in the loop in terms of the derivative of cos(a) sin(a) sin(0) A dr cos(o) sin(es) 4 d 1 cos(8) C 14 sin(0) a do V 7 8 9 5 6 14 1 2 3 . 4 NO 0 CE KH TE B TAFE Ctheexpertta.com Grade Summary Deductions Pontial (0% 100% Submissions Artemptr remainines (per attempt detailed view
Status for view Status Completed Partial Completed (14%) Problem 4: A wire, bent into a rectangle with sides a 0.075 m and b=0.015 m. is in a magnetic field B directed perpendicularly to the face of the wire, as shown. The perpendicular component is a function of time as B(1)-Asin(est), where 4-0.25 T. 6-4 rad's. In this problem. take the normal vector to the surface of the loop to be parallel to the magnetic field. Completed -tracking i 7079-13-4A-44900A-32171. In veedance with Expert TAS Terms of Service man & 25% Part (a) Express the magnetic flux going through the wire, ,25% Part (b) Express the the emf, e, induced in the loop in terms of the derivative of &25% Part (c) Find the emf, E, induced in the loop in terms of a, b, 4, m, and r. costa) cos(0) sin() a do cos(ost) sin(a) sin(9) A 1 Submit cos(p) sintest) Hid 6 b V terms of a, b, 4, es, and t ( 7 8 9 45 6 123 0 4 NO MONO SYSHAR Tubes I give sp Feedback: % dediction per feedback. B |||| Otheexpertta.com Grade Summary Deductions Potential 8% 100% Submissions Attempts remaining (per attempt)
tus. r N MIN pleted al spleted mpleted (14%) Problem 4: A wire, bent into a rectangle with sides a 0.075 m and b 0.015 m, is in a magnetic field B directed perpendicularly to the face of the wire, as shown. The perpendicular component is a function of time as B(1) Asin(est), where 4-0.25 T. -4 rad's. In this problem, take the normal vector to the surface of the loop to be parallel to the magnetic field. Opticking 75479-15-9A-44-400A-02171. cadw with Eaper TAY Toms of Servi 25% Part (a) Express the magnetic flux going through the wire, , in terms of o, b, d, e, and t 25% Part (b) Express the the emf, e, induced in the loop in terms of the derivative of & 25% Part (c) Find the emf, e, induced in the loop in terms of a, b, 4, s, and r &25% Part (d) Calculate the magnitude of the emfatr-62 in V. sind) coil) cotan asin() atant) acolant) acos( cotanh Degrees O Kadians ( In NO C 7 N 9 5 4 123 0 A B |||| Ctheexpertta.com Grade Summary Dedic Pal 100% Sabundos Alempiin! (per detailed view