Help me with this conclusion. Good evening, Class. You will be writing a mock conlusion for your practice report. This
Posted: Mon Jul 11, 2022 1:14 pm
Help me with this conclusion.Good evening, Class. You will be writing a mock conlusion for yourpractice report. This exercise will get you ready to write a reallab report assignment in the future. Also, this is not going to bemarked but follow the information below. Goodnight!NOTE: Please type out the question instead of writing downthe mock conclusion sentence in the paper.Guidance: Was your hypothesis correct? Referto your graphs and diagrams to validate or invalidate it. Indicatefuture studies that could be completed to further gather data tofurther investigate your testable question or improve theexperimental design.Name of the lab: Free falling motion lab.Testable question: How does position dependon time on a free falling motion, for short distance, near thesurface of the earth?Hypothesis: If an object is in free-fallmotion for a certain period of time, (according to the time)acceleration occurs and velocity will increase linearly. This isbecause gravitational acceleration on earth is constant, thedistance an object falls is proportional to the time spent falling.While the velocity-time graph projects a linear increase, itsposition will experience an exponential increase as time goes on.Thus, position depends quadratically on time (due to the paraboliccurve).
Reference:
Graph 1: Vertical position y (m) vs. Time t (s) - Small ball. ● Vertical position y (m) 3.57E-03 +8.1x + 483x^2 Vertical position y (m) 125 100 75 50 25 0 0.0 GRAPHS Position vs. Time for the balls. 0.1 0.2 Time t (s) 0.3 Figure 1: This graph shows the position and corresponding time of the small ball dropping. (Each point is measured 9 frame/s apart.) 0.4 Graph 2: Vertical position y (m) vs. Time t (s) - Large dodge ball. ● Vertical position y (m) -0.286 +33.8x+428x^2 vertical position y (m) 125 100 75 50 25 0 0.0 0.1 0.2 Time t (s) Figure 2: This graph shows the position and corresponding time of the large dodge ball dropping. (Each point is measured 9 frame/s apart.) 0.3 0.4
Times (s) 0 0.0375 0.075 0.1125 0.15 0.1875 0.225 0.2625 0.3 0.3375 0.375 0.4125 0.45 0.4875 TABLE OF OBSERVATIONS Vertical position y (m) 0 1 3 8 12 18 26 35 46 58 71 86 102 118 Given: Increase in position as same interval time progresses. Both data shows quadratic relationship in the graph. Figure 1: This data shows the position and corresponding time of the small ball dropping. (Each point is measured 9 frame/s apart.) This eventually show quadratic relation in the graph. Times (s) 0 0.0375 0.075 0.1125 0.15 0.1875 0.225 0.2625 0.3 0.3375 0.375 0.4125 0.45 Vertical position y (m) 0 2 4 8 14 22 30 38 48 60 72 86 102 Figure 2: This data shows the position and corresponding time of the large dodge ball dropping. (Each point is measured 9 frame. apart.) This eventually show quadratic reation. in the graph.
120 T DIAGRAM AND VIDEOS 138
Conclusion In conclusion the hypothesis stated that if the displacement of the toy car is large in length, then the acceleration will also be on the larger side. This is because the velocity of the toy car is dependent on the car's displacement during motion. The acceleration of the car is dependent on the velocity. If the velocity increases uniformly then the acceleration will increase at the same rate because acceleration is in relation to the change in velocity over time hence, acceleration is dependent on the displacement According to the data, table 3 and 4, it is proven that the hypothesis is correct. When looking at the calculations of the displacements and acceleration using a velocity-time graph, the greater the displacement, the greater the acceleration. Position 3 had a displacement of 1.80m, and an acceleration of -0.19 m/s² [E]. Both the displacement and acceleration are larger than position 2 since the displacement of position 2 is 1.76m, and the acceleration is -0.15 m/s² [E]. The smallest displacement and acceleration is position 1. The displacement is 0.74 m and the acceleration of - 0.14 m/s² [E]. This proves that if the displacement of the toy car is large in length, then the acceleration will also be on the larger side.
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Times (s) 0 0.0375 0.075 0.1125 0.15 0.1875 0.225 0.2625 0.3 0.3375 0.375 0.4125 0.45 0.4875 TABLE OF OBSERVATIONS Vertical position y (m) 0 1 3 8 12 18 26 35 46 58 71 86 102 118 Given: Increase in position as same interval time progresses. Both data shows quadratic relationship in the graph. Figure 1: This data shows the position and corresponding time of the small ball dropping. (Each point is measured 9 frame/s apart.) This eventually show quadratic relation in the graph. Times (s) 0 0.0375 0.075 0.1125 0.15 0.1875 0.225 0.2625 0.3 0.3375 0.375 0.4125 0.45 Vertical position y (m) 0 2 4 8 14 22 30 38 48 60 72 86 102 Figure 2: This data shows the position and corresponding time of the large dodge ball dropping. (Each point is measured 9 frame. apart.) This eventually show quadratic reation. in the graph.
120 T DIAGRAM AND VIDEOS 138
Conclusion In conclusion the hypothesis stated that if the displacement of the toy car is large in length, then the acceleration will also be on the larger side. This is because the velocity of the toy car is dependent on the car's displacement during motion. The acceleration of the car is dependent on the velocity. If the velocity increases uniformly then the acceleration will increase at the same rate because acceleration is in relation to the change in velocity over time hence, acceleration is dependent on the displacement According to the data, table 3 and 4, it is proven that the hypothesis is correct. When looking at the calculations of the displacements and acceleration using a velocity-time graph, the greater the displacement, the greater the acceleration. Position 3 had a displacement of 1.80m, and an acceleration of -0.19 m/s² [E]. Both the displacement and acceleration are larger than position 2 since the displacement of position 2 is 1.76m, and the acceleration is -0.15 m/s² [E]. The smallest displacement and acceleration is position 1. The displacement is 0.74 m and the acceleration of - 0.14 m/s² [E]. This proves that if the displacement of the toy car is large in length, then the acceleration will also be on the larger side.