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answerhappygod
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001 10.0 points A descending elevator of mass 410 kg is uni- formly decelerated to rest over a distance of 4 m by a cable in which the tension is 5053 N. The acceleration due to gravity is 9.8 m/s². v = vi - Vi 4 m Cable 410 kg Elevator v=0* Calculate the speed v; of the elevator at the beginning of the 4 m descent. Answer in units of m/s.
001 10.0 points A descending elevator of mass 410 kg is uni- formly decelerated to rest over a distance of 4 m by a cable in which the tension is 5053 N. The acceleration due to gravity is 9.8 m/s². v = vi - Vi 4 m Cable 410 kg Elevator v=0* Calculate the speed v; of the elevator at the beginning of the 4 m descent. Answer in units of m/s.