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Two charges of 91 = 1.8 µC and 92 P + 9₁ d = -2.9 μC are d = 0.58 m apart at two vertices of an equilateral triangle as
Posted: Mon Jul 11, 2022 12:59 pm
by answerhappygod
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Two charges of 91 = 1.8 µC and 92 P + 9₁ d = -2.9 μC are d = 0.58 m apart at two vertices of an equilateral triangle as in the figure below. 9₂ (a) What is the electric potential due to the 1.8-μC charge at the third vertex, point P? V (b) What is the electric potential due to the -2.9-μC charge at P? V (c) Find the total electric potential at P. V (d) What is the work required to move a 3.6-µC charge from infinity to P? J