First read about Leontief Economic Models in Section 1.6 of the text. Now consider an exchange model economy which has f
Posted: Mon Jul 11, 2022 12:49 pm
First read about Leontief Economic Models in Section 1.6 of the text. Now consider an exchange model economy which has five sectors, Chemicals, Metals, Fuels, Power and Agriculture; and assume the matrix T below gives an exchange table for this economy: T= C M F P A C .20 .17 .25 .20 .10 .20 .10 .30 0 M .25 F .05 .20 .10 .15 .10 P .10 .28 .40 .20 0 A .40 .15 .15 .15 .80 Notice that each column of T sums to one, indicating that all output of each sector is distributed among the five sectors, as should be the case in an exchange economy. The system of equations Tx = x must be satisfied for the economy to be in equilibrium. As you saw above, this is equivalent to the system Bx = 0. (1) Write out the five equations in the equation Tx= x. (2) Obtain a homogeneous linear system Br = 0 equivalent to Tx= x. What is B? Hint: Collect the like terms after moving all non-zero terms to LHS. (3) (Optional) Solve Bx = 0 directly using any kind linear system solver provided by any computing tools. Specify what calculator or computing language you used. (4) Reduce augmented matrix [B10] to RREF form step by step. You may use ei- ther hand-computation or programming. Attach codes at the end of the report if you used programming. A reference to python coding for Gaussian elimination is HERE, and video is HERE (5) Write the general solution of Br = 0. (6) Suppose that the economy described above is in equilibrium and TA = 100 million dollars. Calculate the values of the outputs of the other sectors. (7) As already observed, each column of T sums to one. Consider how you obtained B from T and explain why each column of B must sum to zero. (8) (Bonus 1 pt) Let B be any square matrix with the property that each column of B sums to zero. Explain why the reduced echelon form of B must have a row of zeros. Hint: The proof has two steps: ● In step 1, we can prove (how?) that Br = 0 must have infinitely many solutions due to its each column sum to zero. In step 2, to the contrary, if we assume the last row of REF for B is non- zero, we can show (how?) the uniqueness of Br = 0. But this leads to a contradiction and completes the desired proof.
1 0 0 0 1 0 0 1 0 OOO но 0 0 0 1 -6508/23381 -4390/23381 -4720/23381 -4710/23381 0