A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in
Posted: Mon Jul 11, 2022 12:08 pm
A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in motion from the equilibrium position with a downward velocity of 9 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second) Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second. y= ((9sqrt6)/48)(e^(-16+4sqrt6t))-((9sqrt6)/48) (e^(-16-4sqrt6t))