Find the solution of the given initial value problem: y"+y' = sec(t), y(0) = 6, y'(0) = 3, y'(0) = −4. y(t) = 2+4 cos(t)
Posted: Mon Jul 11, 2022 12:01 pm
Find the solution of the given initial value problem: y"+y' = sec(t), y(0) = 6, y'(0) = 3, y'(0) = −4. y(t) = 2+4 cos(t) + 4 sin(t) — t cos(t) + sin(t) In(cos(t)) X