An apparel company makes blue jeans and leather pants. Heights of adult women are approximately normally distributed wi
Posted: Mon Jul 11, 2022 11:56 am
An apparel company makes blue jeans and leather pants. Heights of adult women are approximately normally distributedwith a mean of 64.5 inches and a standard deviation of 2.5inches.
7. Use your TI to generate 30 data values representingwomen. MATH →PROB→6:randNorm(64.5, 2.5, 30) for the TI 83 or µ = 64.5, σ =2.5, trials = 30 for the TI 84→STO→L1→Enter. Next pressSTAT→2:SortA(→L1→Enter. Now go to your list and write downthe 30 data values. Round to 2 decimal places.
8. Use the STAT function of your calculator to find thesample mean and sample standard deviation for your generated data.Round to two decimal places.
Mean
Standard deviation
Use these sample statistics (sample mean and sample standarddeviation) when computing questions 9 though 11.
9. What percent of female adults are taller than 5 feet 6inches? Show all work which includes what was entered intothe calculator.
10. What percent of female adults are shorter than 5 feet2 inches? Show all work which includes what was entered intothe calculator.
11. What percent of female adult heights are between 60inches and 56 inches? Show all work which includes what was enteredinto the calculator.12. Compare your results for questions 9 through 11 to yourgenerated data. Do you get the same results? How do thepercentages compare? Answer in a complete sentence.
Because of the high cost of leather, the company has decided theycannot profitably make leather pants in all sizes. Use yourcalculator to find the heights corresponding to the followingpercentages. These are the heights of the shortest and tallestfemales who can purchase leather pants from this company. Hint: Use the population summary statistics.
13. The bottom 13%. Show all work which includeswhat was entered into the calculator.
14. The upper 15%. Show all work which includes whatwas entered into the calculator.
15. Compare your results for questions 13 and 14 to yourgenerated data. Do you get the same results? Are theheights similar? Answer in a complete sentence.
7. Use your TI to generate 30 data values representingwomen. MATH →PROB→6:randNorm(64.5, 2.5, 30) for the TI 83 or µ = 64.5, σ =2.5, trials = 30 for the TI 84→STO→L1→Enter. Next pressSTAT→2:SortA(→L1→Enter. Now go to your list and write downthe 30 data values. Round to 2 decimal places.
8. Use the STAT function of your calculator to find thesample mean and sample standard deviation for your generated data.Round to two decimal places.
Mean
Standard deviation
Use these sample statistics (sample mean and sample standarddeviation) when computing questions 9 though 11.
9. What percent of female adults are taller than 5 feet 6inches? Show all work which includes what was entered intothe calculator.
10. What percent of female adults are shorter than 5 feet2 inches? Show all work which includes what was entered intothe calculator.
11. What percent of female adult heights are between 60inches and 56 inches? Show all work which includes what was enteredinto the calculator.12. Compare your results for questions 9 through 11 to yourgenerated data. Do you get the same results? How do thepercentages compare? Answer in a complete sentence.
Because of the high cost of leather, the company has decided theycannot profitably make leather pants in all sizes. Use yourcalculator to find the heights corresponding to the followingpercentages. These are the heights of the shortest and tallestfemales who can purchase leather pants from this company. Hint: Use the population summary statistics.
13. The bottom 13%. Show all work which includeswhat was entered into the calculator.
14. The upper 15%. Show all work which includes whatwas entered into the calculator.
15. Compare your results for questions 13 and 14 to yourgenerated data. Do you get the same results? Are theheights similar? Answer in a complete sentence.