Answer Happy

Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean = 26.9 kilograms and standard deviation = 3.6 kilograms. Let x be the weight of a fawn in kilograms. The Standard Normal Distribution (-0, cr=1) (b) -X For parts (a), (b), and (c), convert the x intervals to z intervals. (For each answer, enter a number. Round your answers to two decimal places.) (a) x < 30 Z< <Z (1) 19 < x (Fill in the blank. A blank is represented by <Z< first blank second blank (c) 32 < x < 35 (Fill in the blanks. A blank is represented by -2 (e) < 1.28 -1 68% of area 95% of area 99,7% of area <x< For parts (d), (e), and (f), convert the z intervals to x intervals. (For each answer, enter a number. Round your answers to one decimal place.) (d) -2.17 <z (Fill in the blank. A blank is represented by .) first blank second blank -1.99 <2<1.44 (Fill in the blanks. A blank is represented by .) There are two answer blanks.) . There are two answer blanks.) (g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above. O Yes. This weight is 3.58 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. O Yes. This weight is 1.79 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. O It would have a negative z, such as -2. O It would have a z of 0. O No. This weight is 3.58 standard deviations below the mean; 14 kg is a normal weight for a fawn. O No. This weight is 3.58 standard deviations above the mean; 14 kg is an unusually high weight for a fawn. O No. This weight is 1.79 standard deviations above the mean; 14 kg is an unusually high weight for a fawn. (h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, -2, or 3? Explain. O It would have a large positive z, such as 3.