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Posted: **Mon Jul 11, 2022 11:55 am**

: Question 2 Answer The Following 1 Xt125 Solve For P 0 5 X 1 5 2 Xx Solve For P X 1 3 X F10 125 Solve For P 1 (93.38 KiB) Viewed 27 times

Question 2 Answer the following: 1. Xt125 solve for P(-0.5 < X < 1.5) 2. XX solve for P(X ≤ 1) 3. X~ F10,125 solve for P(X> 2.519) 4. X F1,14 solve for P(X> 1.44) n =) 120 = 00 th square F₁, n Fm, n JU n-> ∞ nive 3718 -> N(0, 1) Į x² square x'm 2 m page 2 of 2