Answer Happy

Posted: **Mon Jul 11, 2022 11:55 am**

: 49 51 1 46 9 49 45 4 47 5 49 7 51 8 51 53 1 48 8 51 47 49 1 48 2 50 3 49 51 1 48 4 50 5 The Table Sh 1 (41.62 KiB) Viewed 66 times

: 49 51 1 46 9 49 45 4 47 5 49 7 51 8 51 53 1 48 8 51 47 49 1 48 2 50 3 49 51 1 48 4 50 5 The Table Sh 2 (18.39 KiB) Viewed 66 times

(49,51.1) (46.9,49) (45.4,47.5) (49.7,51.8) (51,53.1) (48.8,51) (47,49.1) (48.2,50.3) (49,51.1) (48.4,50.5) The table shows ten 60% CI's for u taken from a population that is N(49, 4). = a. How many of the CI's would you expect to contain μ b. How many of the CI's actually contain = 49? Submit Question 49?
To build a 98% CI for the mean of a population for which is 18, you take a random sample of 34 values and find that the sample mean is 212.6. Round all intermediate calculations to two decimals, then construct the CI and enter like this: (min,max). Be sure to include the parentheses or you will be marked wrong. Note: if you use a built-in Cl command on a calculator/computer, you might get marked wrong due to rounding. Use the formulas given in the text/notes. Submit Question