Answer Happy

Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.33 days to watch the entire first season of a television series, with a standard deviation of 3.98 days. Scarlett is an analyst for an online television and movie streaming service Company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample z-test, with significance level of a = 0.05, to test the null hypothesis, Ho μ = 6.33 days, against the alternative hypothesis, H₁ μ< 6.33 days. The variable u is the mean amount of time, in days, that it takes for customers to watch the first season of a television series. Scarlett selects a simple random sample of 840 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table. Sample size n 840 Sample mean x 6.14 Standard error SE 0.1373 Compute the P-value for Scarlett's hypothesis test directly using a normalcdf function on a TI calculator or by using software. You may find some software manuals helpful. Provide your answer with precision to four decimal places. Avoid rounding until the final step.
P-value = Select the accurate statement regarding Scarlett's test decision if she tests at a significance level of a = 0.05. : 0.05. O Scarlett should fail to reject the null hypothesis because the P-value is less than the value, a = Scarlett should reject the null hypothesis because the P-value is less than the value, a = 0.05. Scarlett should fail to reject the null hypothesis because the P-value is greater than the value, a = 0.05. Scarlett should reject the null hypothesis because the P-value is greater than the value, a = 0.05. Scarlett should fail to reject the null hypothesis because the P-value is greater than the value, = 0.025.