Find the surface area of the volume generated when the curve y=(sqrt(x)) revolves around the x axis from (1,1) to (4,2)
Posted: Mon Jul 11, 2022 11:06 am
Find the surface area of the volume generated when the curvey=(sqrt(x)) revolves around the x axis from (1,1) to (4,2) asshown
y 2 1 0 -1 -2 1 2 X y = √x 3 - 2 1 0 -2 -1 Z
y 2 1 0 -1 -2 1 2 X y = √x 3 - 2 1 0 -2 -1 Z