Evaluate the integral. -32e² - 160 -dz Submit answer e2x + 12e +32 Answer: +C Hint: let u= e so that due dr and thus dr
Posted: Mon Jul 11, 2022 11:04 am
Evaluate the integral. -32e² - 160 -dz Submit answer e2x + 12e +32 Answer: +C Hint: let u= e so that due dr and thus dr = du/u. This substitution converts the integrand into a rational function in u, which can be integrated after partial fraction decomposition.