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Solve the following initial value problem for 𝑥 as a function of 𝑡: (𝑡^2 + 3𝑡) 𝑑𝑥/𝑑𝑡 = 3𝑥 + 3; 𝑡 > 0; 𝑥(1) = 3

Posted: Mon Jul 11, 2022 10:47 am
by answerhappygod
Solve the following initial value problem for ๐‘ฅ as a function of๐‘ก: (๐‘ก^2 + 3๐‘ก) ๐‘‘๐‘ฅ/๐‘‘๐‘ก = 3๐‘ฅ + 3; ๐‘ก > 0; ๐‘ฅ(1) = 3