Answer Happy • k(x) = i(x)/(j(x))², So k'(x) = ? i'(x)(j'(x))² i'(x)(j'(x))² + 2i(x)(j(x))² i'(x) (j(x))² + 2i(x)j(x)j'(x) i'(x)/(j(x))

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k(x) = i(x)/(j(x))², So k'(x) = ? i'(x)(j'(x))² i'(x)(j'(x))² + 2i(x)(j(x))² i'(x) (j(x))² + 2i(x)j(x)j'(x) i'(x)/(j(x))

Posted: Mon Jul 11, 2022 10:44 am

by answerhappygod

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k(x) = i(x)/(j(x))², So k'(x) = ? i'(x)(j'(x))² i'(x)(j'(x))² + 2i(x)(j(x))² i'(x) (j(x))² + 2i(x)j(x)j'(x) i'(x)/(j(x))² + 2i(x)j'(x)/(x) i'(x)/(j(x))² - 2i(x)j'(x) / (j(x))³