Answer Happy • h(x) = (f(x))²g(x), So h'(x) = ? 2f(x)f'(x)g(x) + (f(x))²g'(x) 2f(x)²g(x) + f'(x)g'(x) (f(x))²f'(x)g'(x) 2f(x)f'(x)g'(x)

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h(x) = (f(x))²g(x), So h'(x) = ? 2f(x)f'(x)g(x) + (f(x))²g'(x) 2f(x)²g(x) + f'(x)g'(x) (f(x))²f'(x)g'(x) 2f(x)f'(x)g'(x)

Posted: Mon Jul 11, 2022 10:44 am

by answerhappygod

: H X F X G X So H X 2f X F X G X F X G X 2f X G X F X G X F X F X G X 2f X F X G X 1 (56.16 KiB) Viewed 29 times

h(x) = (f(x))²g(x), So h'(x) = ? 2f(x)f'(x)g(x) + (f(x))²g'(x) 2f(x)²g(x) + f'(x)g'(x) (f(x))²f'(x)g'(x) 2f(x)f'(x)g'(x) 2f(x)f'(x)g(x)