Answer Happy

Make sure which one is which and fill in the blanks 1-6 usinga~n.
Plz fill in the blanks 1-6. Find the equation of the tangent line at the point (1, √2) on the ellipse 2x² + 5y² = 12. F(x,y)=2x² + 5y²-12 Now that F(1, √2)=0, Fy(1, √2) =(1) # 0, a negative function y=f(x) exists near (1,√2)). F(1, √√2) = 0, Fy(1,√2) = (1) 0 We can calculate f'(x). So if we find f'(x) from the negative function theorem and divide it, f'(x) = Therefore, f'(1)=(4) is obtained because (x,y)=(1,√2). Furthermore, f(1)=√2 is obtained. The equation of the tangent line is y=(5)x+(6). f'(1) (4) y = (2) (3) a. 2x 9. (5) x + (6) 6√/2 5 b. 2x - 6 h. 4√2 5 c. 10√/2 i. 2√2 5 d. 10√/2 - 12 j. √2 e. 5y √2 f. 5y - 6 2√/2 5 4√2 5 m.- n. 6√2 5