Solve on [0, 2rt). Choose all solutions. sin x > sin 2x [n/3, n] 10, r/3] (n. 5n/3) 15n/3, 2n) [n/2, 3n/2] 10./2] Solve
Posted: Mon Jul 11, 2022 10:32 am
- Solve On 0 2rt Choose All Solutions Sin X Sin 2x N 3 N 10 R 3 N 5n 3 15n 3 2n N 2 3n 2 10 2 Solve 1 (25.41 KiB) Viewed 35 times
- Solve On 0 2rt Choose All Solutions Sin X Sin 2x N 3 N 10 R 3 N 5n 3 15n 3 2n N 2 3n 2 10 2 Solve 2 (33.88 KiB) Viewed 35 times
Solve on [0, 2r). Choose all solutions. 2cos 2x-√3-0 n/12 1/6 11/6 11/12 13π/6 13m/12 23/12 1/3