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Question 17 (10 points) What volume of water vapor gas would be produced from the combustion of 589.03 grams of propane
Posted: Sun Jul 10, 2022 4:15 pm
by answerhappygod
- Question 17 10 Points What Volume Of Water Vapor Gas Would Be Produced From The Combustion Of 589 03 Grams Of Propane 1 (27.5 KiB) Viewed 37 times
Question 17 (10 points) What volume of water vapor gas would be produced from the combustion of 589.03 grams of propane (C3Hg) with 2,857.44 grams of oxygen gas, under a pressure of 0.96 atm and a temperature of 350. degrees C? Given: C3H8(g) + 5 O2(g) ---> 3 CO₂(g) + 4H₂O(g) (OR C3 Hg ("g") + 5 O₂ ("g") right arrow 3 C O₂ ("g") + 4H₂O ("g") L atm mol K Do not type units with your answer Your Answer: R= = 0.08206- Answer