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1. For each nuclear reaction below, provide the following.reaction (1): AZX + 0−1e → 23592U reaction (2): AZX → 15261Pm + 0−1e reaction (3): 16171Lu → 16170Yb + AZX reaction (4): 14354Xe → 14355Cs + AZX(In AZX, X is the symbol for a chemical element or subatomic particle, Z is the atomic number of the element or charge on the subatomic particle, and A is the mass number of the atomic nucleus or mass of the subatomic particle.)Identify the unknown reactant or product shown as AZX. (Enter your answer in the form AXZ.)reaction (1): reaction (2):reaction (3):reaction (4):Write the complete equation. (Enter your answer in the form AXZ.)reaction (1): reaction (2):reaction (3):reaction (4):2. The nuclear decay series for neptunium-237 can be summarized as follows.23793Np → 23391Pa → 23392U → 22990Th → 22588Ra → 22589Ac → 22187Fr → 21785At → 21383Bi → 21384Po → 20982Pb → 20983Bi → 20581Tl(a) Write balanced equations to describe the first 4 reactions starting with 23793Np in this series. (Enter your answer in the form AXZ.) first reaction: second reaction:third reaction:fourth reaction:
reaction (1): AZX + 0−1e → 23592U reaction (2): AZX → 15261Pm + 0−1e reaction (3): 16171Lu → 16170Yb + AZX reaction (4): 14354Xe → 14355Cs + AZX
(In AZX, X is the symbol for a chemical element or subatomic particle, Z is the atomic number of the element or charge on the subatomic particle, and A is the mass number of the atomic nucleus or mass of the subatomic particle.)
reaction (1):
reaction (2):
reaction (3):
reaction (4):
Write the complete equation. (Enter your answer in the form AXZ.)
reaction (1): reaction (2):reaction (3):reaction (4):2. The nuclear decay series for neptunium-237 can be summarized as follows.23793Np → 23391Pa → 23392U → 22990Th → 22588Ra → 22589Ac → 22187Fr → 21785At → 21383Bi → 21384Po → 20982Pb → 20983Bi → 20581Tl(a) Write balanced equations to describe the first 4 reactions starting with 23793Np in this series. (Enter your answer in the form AXZ.) first reaction: second reaction:third reaction:fourth reaction:
reaction (1):
reaction (2):
reaction (3):
reaction (4):
2. The nuclear decay series for neptunium-237 can be summarized as follows.
23793Np → 23391Pa → 23392U → 22990Th → 22588Ra → 22589Ac → 22187Fr → 21785At → 21383Bi → 21384Po → 20982Pb → 20983Bi → 20581Tl
(a) Write balanced equations to describe the first 4 reactions starting with 23793Np in this series. (Enter your answer in the form AXZ.) first reaction:
second reaction:
third reaction:
fourth reaction:
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The nuclear decay series for neptunium-237 can be summarized as follows. 237 225 225 AC-221 Fr 217 At- 213 1 A form ^x.) first reaction: Po Pb-2008-201 (a) Write balanced equations to describe the first 4 reactions starting with 233Np in this series. (Enter your answer in the 93" chemPad XX" second reaction: chemPad third reaction: chemPad fourth reaction: emPad XX Supporting Materials 209 Periodic Table Additional Materials Tutorial Strategy Video Help Greek Help Greek Help Greek (b) Determine the numbers and types of emissions involved in the first 6 reactions starting with Np in this series. 237 is/are beta emission(s), In the first 6 reactions of this series, is/are beta emission(s), and there is/are Help Greek Factors 205. Constants and is/are alpha emission(s), electron capture event(s). Supplemental Data