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In (P2/165)= (38.56*1000/8.314)*(1/318- 1/338) In (P2/165)=0.8, P2= 391 mm Hg, the vapor pressure of ethanol at 65 Deg.c

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In (P2/165)= (38.56*1000/8.314)*(1/318- 1/338) In (P2/165)=0.8, P2= 391 mm Hg, the vapor pressure of ethanol at 65 Deg.c

Posted: Sun Jul 10, 2022 3:48 pm
by answerhappygod
In P2 165 38 56 1000 8 314 1 318 1 338 In P2 165 0 8 P2 391 Mm Hg The Vapor Pressure Of Ethanol At 65 Deg C 1
In P2 165 38 56 1000 8 314 1 318 1 338 In P2 165 0 8 P2 391 Mm Hg The Vapor Pressure Of Ethanol At 65 Deg C 1 (17.73 KiB) Viewed 32 times
In (P2/165)= (38.56*1000/8.314)*(1/318- 1/338) In (P2/165)=0.8, P2= 391 mm Hg, the vapor pressure of ethanol at 65 Deg.c is 391 mm Hg
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