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Two charges of 91 = 1.4 µC and 92 P + 9₁ d d d = -2.3 µC are d = 0.48 m apart at two vertices of an equilateral triangle
Posted: Sun Jul 10, 2022 3:41 pm
by answerhappygod
- Two Charges Of 91 1 4 Uc And 92 P 9 D D D 2 3 Uc Are D 0 48 M Apart At Two Vertices Of An Equilateral Triangle 1 (330.75 KiB) Viewed 43 times
Two charges of 91 = 1.4 µC and 92 P + 9₁ d d d = -2.3 µC are d = 0.48 m apart at two vertices of an equilateral triangle as in the figure below. 92 (a) What is the electric potential due to the 1.4-µC charge at the third vertex, point P? V (b) What is the electric potential due to the -2.3-µC charge at P? V (c) Find the total electric potential at P. V (d) What is the work required to move a 4.0-μC charge from infinity to P? J