Answer Happy • In the circuit of Figure, the equivalent capacitance is C₂= 1.00 μF- O 1.50 μF O 2.67 µF O 5.0 uF O 0.8 μF :C₁ = 2.00 μF

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In the circuit of Figure, the equivalent capacitance is C₂= 1.00 μF- O 1.50 μF O 2.67 µF O 5.0 uF O 0.8 μF :C₁ = 2.00 μF

Posted: Sun Jul 10, 2022 11:54 am

by answerhappygod

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In the circuit of Figure, the equivalent capacitance is C₂= 1.00 μF- O 1.50 μF O 2.67 µF O 5.0 uF O 0.8 μF :C₁ = 2.00 μF :C₁ = 2.00 μF