Capacity, gal/min 0 20 40 60 80 100 120 140 Load, feet 110 106 90 63 41 22 12 7 Efficiency, % 0 29.2 40.0 45.0 47.0 48.3

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answerhappygod
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Capacity, gal/min 0 20 40 60 80 100 120 140 Load, feet 110 106 90 63 41 22 12 7 Efficiency, % 0 29.2 40.0 45.0 47.0 48.3

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Capacity Gal Min 0 20 40 60 80 100 120 140 Load Feet 110 106 90 63 41 22 12 7 Efficiency 0 29 2 40 0 45 0 47 0 48 3 1
Capacity Gal Min 0 20 40 60 80 100 120 140 Load Feet 110 106 90 63 41 22 12 7 Efficiency 0 29 2 40 0 45 0 47 0 48 3 1 (72.68 KiB) Viewed 53 times
For the following conditions obtain from figure 13.30 of Robert Mott's book answer the following questions.
1. Q=450L/min, H=45m, Efficiency, impeller diameter and Power
2. Q= 1200L/min, Dimpulsor=11 1/2in, obtain from the graph: head, power and efficiency.
3. For what point is the NPSH calculated in a pumping system? Why?
4. In the case where cavitation occurs, what would you recommend to solve the problem.
Capacity, gal/min 0 20 40 60 80 100 120 140 Load, feet 110 106 90 63 41 22 12 7 Efficiency, % 0 29.2 40.0 45.0 47.0 48.3 46.5 40.0
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