Design the beam and column system shown in the figure below (NOTE: The support conditions are not realistic and are only
Posted: Sun Jul 10, 2022 11:47 am
Design the beam and column system shown in the figure below(NOTE: The support conditions are not realistic and are only usedfor class purpose to simplify structural analysis and designprocess). Check for flexure, shear and deflection in beam. Wheneveryou use code, please also report the page number that you referredto and the values that you are looking into. Units should bementioned wherever applicable. All intermediate
steps should be shown for partial credit.
x = 5.87
DL: (52 + 8x) k LL: (78 + 12x) k A (18+ x) ft. - 5 ft. C (16+ x) ft. (65+15x) k (85+ 20x) k E E (4 + x) k/ft (6 + x) k/ft B OPTIONAL (45+25x) k (70+ 15x) k (4 + x) k/ft (6 + x) k /ft (52 + 8x) k (78 + 12x) k B D
Legend: A (55 + x) k (135 + x) k (125+x) k (175 + x) k (13 + x) ft. Symbol 1 x o (20+x) k (10+x) k (30 + x) ft с E (75+ x) k (80+ x) k B Meaning Beam section Column section (250+x) k (105 + x) k Bracing at center of the beam span Concentrated load D Uniformly distributed load Hinge support Roller support Fixed support DL: (20 + x) k LL: (10 + x) k Span= (30+ x) ft long
Use steel with Fy = 50 ksi. Allowable deflection is 1/360 of the span of the beam. Assume that the sections W 21 x 62 are available to you for no cost. Assume the cost of steel for any other sections = $ 4.2/lb. (finished). In case you do not find a relevant constant for a loading condition (Cb, Cv or C₁), use the constant that corresponds to the worst-case scenario. (NOTE: The only intent of this instruction is to simplify the problem. Calculated values of the constants MUST be used in real design.) Please calculate, i) Minimum cost of the beam system (when W 21 x 62 is free) ii) Most economic cost of the beam system if the sections W 21 x 62 were not freely available iii) Most economical cost of column system. OPTIONAL: The concentrated load provided on top of UDL in mid-span of beam CD is optional. You will get extra 10% points if you consider it in design. Hint: See Example 9-10. The project is due at 11:59 PM on July 08, 2022, through canvas as a single pdf file. (July 09, 2022, at 11:59 PM for 75% of the grade)
steps should be shown for partial credit.
x = 5.87
- Design The Beam And Column System Shown In The Figure Below Note The Support Conditions Are Not Realistic And Are Only 1 (75.68 KiB) Viewed 41 times
Legend: A (55 + x) k (135 + x) k (125+x) k (175 + x) k (13 + x) ft. Symbol 1 x o (20+x) k (10+x) k (30 + x) ft с E (75+ x) k (80+ x) k B Meaning Beam section Column section (250+x) k (105 + x) k Bracing at center of the beam span Concentrated load D Uniformly distributed load Hinge support Roller support Fixed support DL: (20 + x) k LL: (10 + x) k Span= (30+ x) ft long
Use steel with Fy = 50 ksi. Allowable deflection is 1/360 of the span of the beam. Assume that the sections W 21 x 62 are available to you for no cost. Assume the cost of steel for any other sections = $ 4.2/lb. (finished). In case you do not find a relevant constant for a loading condition (Cb, Cv or C₁), use the constant that corresponds to the worst-case scenario. (NOTE: The only intent of this instruction is to simplify the problem. Calculated values of the constants MUST be used in real design.) Please calculate, i) Minimum cost of the beam system (when W 21 x 62 is free) ii) Most economic cost of the beam system if the sections W 21 x 62 were not freely available iii) Most economical cost of column system. OPTIONAL: The concentrated load provided on top of UDL in mid-span of beam CD is optional. You will get extra 10% points if you consider it in design. Hint: See Example 9-10. The project is due at 11:59 PM on July 08, 2022, through canvas as a single pdf file. (July 09, 2022, at 11:59 PM for 75% of the grade)