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Posted: **Sun Jul 10, 2022 11:44 am**

: Given The Data Below About The Axial Strain Vs Deviator Stress Axial Strain X 0 1 0 2 Deviator Stress Kpa Y 1 (80.49 KiB) Viewed 34 times

: Given The Data Below About The Axial Strain Vs Deviator Stress Axial Strain X 0 1 0 2 Deviator Stress Kpa Y 2 (44.85 KiB) Viewed 34 times

Given the data below about the Axial Strain(%) vs Deviator Stress: Axial Strain (%), X 0 1 0 2 Deviator Stress (kPa), y What is the equation form Using Lagrange Interpolation? 27.227 44.92 3 59.776 oy = 13.6135(x)(x-2)(x-3) - 22.46(x)(x-1)(x-3) + 9.96267(x)(x-1)(x-2) o y = 13.6135(x-1)(x-2)(x-3) - 22.46(x)(x-1)(x-3) + 9.96267(x)(x-1)(x-2) oy = 13.6135(x)(x-2)(x-3) + 22.46(x)(x-1)(x-3) - 9.96267(x)(x-1)(x-2) oy = 13.6135(x-1)(x-2)(x-3) + 22.46(x)(x-1)(x-3) - 9.96267(x)(x-1)(x-2)
Given the following data: X Y 10 15 20 25 30 35 65.76 88.43 122 145 152.6 200.4 Find the Least Square Fit - Linear Fit. And then solve the value of ao. O 14.76895 O 5.078343 O 0.9722 O 0.9860