- 1 (28.81 KiB) Viewed 36 times
有限入 Part C-Results & Calculations Test Ones diffantial prem 10 Water the ag H Teed cooling food, w Air inlet dry but, IL C Air inde wat bulb, 1205 Air atlet dry bith, 13.0 Auteuilet wet buD, C Wer inlet temp, OK Water outlet temp., 16 total coeling load, W Air inlet dry bulb, 11 C Air indet wel hull, 12 °C Air outlet dry balk 0.0 Air cutlet wet helh, 14 °C Mass flow rate of air, kes Water det smp, 150 Water outlet temp, If 'C Wet buth approach, C Am 0.58 DEEG 28.12 21.5. 49% 26.85€ MELC Orifice differential possure, mm 10. Water flows, p 19 Total cooling load, KW Air indet dry buth, C Air inlet wet buih, 125C Air outlet dry bulb, 13 "C Air mutlet wet bulb, 14 "C Water inlet temp. 15°C Water outlet temp#C Wet bulb approach, t HVACSA) Cooling Tower 40.5 2015 25.8% 14.4.2 2222 3622 28.9% 45%6 Test Orifice differential pessure, mm H₂O Water flow rate, g 15 Mass flow rate of air, kers POS 21.1°C 24.0% 23-4 Halk 34.12 20.7°C 25.0°C 1.16 jot lie thin'c 34.1°C 26.1°C 13.1% 34.2% 13.9.20 26.02 28 35:1% 24.6% 33.17 361 37,3% 78.7% 25°C 41.0 23.40€ 22.8°4 22.93 22./20 38 % 26.3.2 26°C +1.5 22.4.6 WAKE 27.82 26.8°C 17-18 x 16 14,46 16.06 YK 28.8°C 22.9°C 36.0°C 34.4°C #2 C 31,0's 160°C 1.5 25.5% 23% 1513 23.4% 43.3 t's 24% Plot the graph of "Approach to wet bul" against total cooling food for alle 1.2 and 3 conditions on the same graph for comparison. Draw the best straight line through the points.