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A boundary between two dielectric materials with relative dielectric permittivities &r1=4 and 8r2=5 lies in the x-y plan
Posted: Sun Jul 10, 2022 11:33 am
by answerhappygod
- A Boundary Between Two Dielectric Materials With Relative Dielectric Permittivities R1 4 And 8r2 5 Lies In The X Y Plan 1 (37.04 KiB) Viewed 52 times
A boundary between two dielectric materials with relative dielectric permittivities &r1=4 and 8r2=5 lies in the x-y plane. The z-axis points from material 1 to material 2. In material 1, at the boundary, the electric field is given by: E₁ = X9 + 4 + 23 Between these two dielectrics is a sheet of negative charge with surface charge density Ps= 8.85x10-11 C/m². co-8.85x10-12 F/m. (Hint: Careful about the orders of magnitude!) 2a) Calculate 01, the angle between E1 and the normal to the boundary. 2b) Calculate E2 at the boundary.