La 14 ise Ubatt 2 Juba USC 2 USCI LI wwm um mm iza T mm mm Vp ty Gold Simulation has to be carried out for the above cir
Posted: Sun Jul 10, 2022 11:32 am
- La 14 Ise Ubatt 2 Juba Usc 2 Usci Li Wwm Um Mm Iza T Mm Mm Vp Ty Gold Simulation Has To Be Carried Out For The Above Cir 1 (49.46 KiB) Viewed 41 times
- La 14 Ise Ubatt 2 Juba Usc 2 Usci Li Wwm Um Mm Iza T Mm Mm Vp Ty Gold Simulation Has To Be Carried Out For The Above Cir 2 (34.27 KiB) Viewed 41 times
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- La 14 Ise Ubatt 2 Juba Usc 2 Usci Li Wwm Um Mm Iza T Mm Mm Vp Ty Gold Simulation Has To Be Carried Out For The Above Cir 5 (43.16 KiB) Viewed 41 times
- La 14 Ise Ubatt 2 Juba Usc 2 Usci Li Wwm Um Mm Iza T Mm Mm Vp Ty Gold Simulation Has To Be Carried Out For The Above Cir 6 (56.16 KiB) Viewed 41 times
X₁ X₂ X3 X4. X5 X₂₂ X7 Xq by 11 ild - Ild PCI-PC! 119 - 11g. hty - by = Volc - V₁* = 1 batt - I batt = ise - Isc = Vet - Ver Veq - Vo₂
Ind V = Vot * * 1₂ Veq - Ver * I2 = 1₂ 1 Izq = 1₂ Ibat = Ibat Isc = 1² Ic de = Vacref
I Ind Pgm1 = 3 Vgd Ind Vcq Vc I'd Ing is * -batt Ppv PHESS PRESS Ppv. Pond ↓ (Real time data) M 1 2 - Reference Value Vigd grid veltage in digo frame Vag Vgg + wh₂ Ind Vgd - w/₂ I2q + R₂ I ₂4 12 - wc VC₂ set to 0. Ppv LPF is = 129 + wcp Vcs * and Isc are obtained from Polar Balance equation + are constants obtained from Grl power. Paid Pac-Pand + Phatt Pse + (can be chosen) is also R₂ 129 + PHESS 0 → Ibatt Isc
2, Adq=d₂-D₂ Ad-Da ___dbatt Pac Vac __dsc_ Dbatt = Dsc can Adtatt-t = Ubatt! - Whatt Dabatt-2 = Ubatt2 - WBattz be obtained Vac V PI In two different ways X Pac → Pac Ddsc_1= Usci - Usc Adse=2= Usc₂-Wsc₂ Kbatt (1- Ubatt-1) + (1-Kbatt) Ubatt 2 Kbatt (1- WBitt!) + (1 - Kbatt) W Batt2 Kot Ksc (1-USCI) + (1- Kac) Usc2 Ksi (1- Wsu) + (1- Ksc) Wsc 2
sdy = K₁ XIV-XS I Didq = K₂ [X34² = 15-1₁2] Odbattl=k3 [Xsatt - X Vox²] K₁, K₂20 ▶ Now Ad's da J Now, dbatt, de to K3, Ky, ks, *₂70 we should use b da, db, de Ad's are related to ds and equations Equations "D's are also given. d₂ = de = dd, dq →y da, ob de de Adbutt-2 = Ky [X6V₁² - X Ibnt] Dagent =K5| = K5 [X5 se-X₂²] V Adge_2 = K₂ [1₂ V₁² - X51₂] above equatery to obtain = Sa - Sa+56 +5€ can be directly Red as gating inputs DC-DC convertex of battery and SC. Ds by following Sa+b+s 3 Sa + Sb +5₂ are switching functions for gasting signals VSI Sa S, S,= 1 er o gate pultes for VSJ