Answer Happy

If water is drained from a vertical cylindrical tank by opening a valve at the base, the water will flow fast when the tank is full and slow down as it continues to drain. As it turns out, the rate at which the water level drops is: dy dt -k√y == where k is a constant depending on the shape of the hole and the cross-sectional area of the tank and drain hole. The depth of the water y is measured in meters and the time t in minutes. If k = 0.7654 and initial fluid level is 3. 5 m, determine the fluid level at time t = 4.5 minutes. Solve by applying fourth order Runge Kutta method use a step of 0.75 minutes and 4 digit decimals